Optimal. Leaf size=95 \[ -\frac {b^3 \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{16 a^{5/2}}+\frac {b^2 \sqrt {a+b x^2}}{16 a^2 x^2}-\frac {\sqrt {a+b x^2}}{6 x^6}-\frac {b \sqrt {a+b x^2}}{24 a x^4} \]
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Rubi [A] time = 0.05, antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {266, 47, 51, 63, 208} \[ \frac {b^2 \sqrt {a+b x^2}}{16 a^2 x^2}-\frac {b^3 \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{16 a^{5/2}}-\frac {b \sqrt {a+b x^2}}{24 a x^4}-\frac {\sqrt {a+b x^2}}{6 x^6} \]
Antiderivative was successfully verified.
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Rule 47
Rule 51
Rule 63
Rule 208
Rule 266
Rubi steps
\begin {align*} \int \frac {\sqrt {a+b x^2}}{x^7} \, dx &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {\sqrt {a+b x}}{x^4} \, dx,x,x^2\right )\\ &=-\frac {\sqrt {a+b x^2}}{6 x^6}+\frac {1}{12} b \operatorname {Subst}\left (\int \frac {1}{x^3 \sqrt {a+b x}} \, dx,x,x^2\right )\\ &=-\frac {\sqrt {a+b x^2}}{6 x^6}-\frac {b \sqrt {a+b x^2}}{24 a x^4}-\frac {b^2 \operatorname {Subst}\left (\int \frac {1}{x^2 \sqrt {a+b x}} \, dx,x,x^2\right )}{16 a}\\ &=-\frac {\sqrt {a+b x^2}}{6 x^6}-\frac {b \sqrt {a+b x^2}}{24 a x^4}+\frac {b^2 \sqrt {a+b x^2}}{16 a^2 x^2}+\frac {b^3 \operatorname {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,x^2\right )}{32 a^2}\\ &=-\frac {\sqrt {a+b x^2}}{6 x^6}-\frac {b \sqrt {a+b x^2}}{24 a x^4}+\frac {b^2 \sqrt {a+b x^2}}{16 a^2 x^2}+\frac {b^2 \operatorname {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x^2}\right )}{16 a^2}\\ &=-\frac {\sqrt {a+b x^2}}{6 x^6}-\frac {b \sqrt {a+b x^2}}{24 a x^4}+\frac {b^2 \sqrt {a+b x^2}}{16 a^2 x^2}-\frac {b^3 \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{16 a^{5/2}}\\ \end {align*}
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Mathematica [C] time = 0.01, size = 39, normalized size = 0.41 \[ \frac {b^3 \left (a+b x^2\right )^{3/2} \, _2F_1\left (\frac {3}{2},4;\frac {5}{2};\frac {b x^2}{a}+1\right )}{3 a^4} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.97, size = 157, normalized size = 1.65 \[ \left [\frac {3 \, \sqrt {a} b^{3} x^{6} \log \left (-\frac {b x^{2} - 2 \, \sqrt {b x^{2} + a} \sqrt {a} + 2 \, a}{x^{2}}\right ) + 2 \, {\left (3 \, a b^{2} x^{4} - 2 \, a^{2} b x^{2} - 8 \, a^{3}\right )} \sqrt {b x^{2} + a}}{96 \, a^{3} x^{6}}, \frac {3 \, \sqrt {-a} b^{3} x^{6} \arctan \left (\frac {\sqrt {-a}}{\sqrt {b x^{2} + a}}\right ) + {\left (3 \, a b^{2} x^{4} - 2 \, a^{2} b x^{2} - 8 \, a^{3}\right )} \sqrt {b x^{2} + a}}{48 \, a^{3} x^{6}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.68, size = 92, normalized size = 0.97 \[ \frac {\frac {3 \, b^{4} \arctan \left (\frac {\sqrt {b x^{2} + a}}{\sqrt {-a}}\right )}{\sqrt {-a} a^{2}} + \frac {3 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} b^{4} - 8 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a b^{4} - 3 \, \sqrt {b x^{2} + a} a^{2} b^{4}}{a^{2} b^{3} x^{6}}}{48 \, b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 105, normalized size = 1.11 \[ -\frac {b^{3} \ln \left (\frac {2 a +2 \sqrt {b \,x^{2}+a}\, \sqrt {a}}{x}\right )}{16 a^{\frac {5}{2}}}+\frac {\sqrt {b \,x^{2}+a}\, b^{3}}{16 a^{3}}-\frac {\left (b \,x^{2}+a \right )^{\frac {3}{2}} b^{2}}{16 a^{3} x^{2}}+\frac {\left (b \,x^{2}+a \right )^{\frac {3}{2}} b}{8 a^{2} x^{4}}-\frac {\left (b \,x^{2}+a \right )^{\frac {3}{2}}}{6 a \,x^{6}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.34, size = 93, normalized size = 0.98 \[ -\frac {b^{3} \operatorname {arsinh}\left (\frac {a}{\sqrt {a b} {\left | x \right |}}\right )}{16 \, a^{\frac {5}{2}}} + \frac {\sqrt {b x^{2} + a} b^{3}}{16 \, a^{3}} - \frac {{\left (b x^{2} + a\right )}^{\frac {3}{2}} b^{2}}{16 \, a^{3} x^{2}} + \frac {{\left (b x^{2} + a\right )}^{\frac {3}{2}} b}{8 \, a^{2} x^{4}} - \frac {{\left (b x^{2} + a\right )}^{\frac {3}{2}}}{6 \, a x^{6}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.94, size = 74, normalized size = 0.78 \[ \frac {{\left (b\,x^2+a\right )}^{5/2}}{16\,a^2\,x^6}-\frac {{\left (b\,x^2+a\right )}^{3/2}}{6\,a\,x^6}-\frac {\sqrt {b\,x^2+a}}{16\,x^6}+\frac {b^3\,\mathrm {atan}\left (\frac {\sqrt {b\,x^2+a}\,1{}\mathrm {i}}{\sqrt {a}}\right )\,1{}\mathrm {i}}{16\,a^{5/2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 5.91, size = 117, normalized size = 1.23 \[ - \frac {a}{6 \sqrt {b} x^{7} \sqrt {\frac {a}{b x^{2}} + 1}} - \frac {5 \sqrt {b}}{24 x^{5} \sqrt {\frac {a}{b x^{2}} + 1}} + \frac {b^{\frac {3}{2}}}{48 a x^{3} \sqrt {\frac {a}{b x^{2}} + 1}} + \frac {b^{\frac {5}{2}}}{16 a^{2} x \sqrt {\frac {a}{b x^{2}} + 1}} - \frac {b^{3} \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} x} \right )}}{16 a^{\frac {5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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